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急!!JAvA试题解决方案(从键盘上输入10个整数,...

package Test; import java.util.Scanner; public class test { public static void main(String[] args) { Scanner sca = new Scanner(System.in); int[] ints = new int[10]; System.out.println("请输入10个数字"); for (int i = 0; i < 10; ...

代码如下: public static void main(String[] args) throws Exception{int[] array = new int[10];Scanner input = new Scanner(System.in);for(int i=0;i

//要采纳哦 import java.util.Scanner; public class Test5 { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Scanner sc=new Scanner(System.in); int a[]=new int[10]; for (int i = 0; ...

代码如下 import java.io.BufferedReader;import java.io.IOException;import java.io.InputStreamReader; public class TenNum { /** * @param args * @throws IOException */ public static void main(String[] args) throws IOException { S...

import java.util.Scanner; public class Test43 { public static void main(String[] args) { System.out.println("请输入10个数字,输入每个数字后以回车结束");// 提示语句,输入一个数要按下回车 Scanner sc = new Scanner(System.in);// 这是...

从键盘上输入10个整数,输出最小值的完整的Java程序如下:(不用数组) import java.util.Scanner; public class C{ public static void main(String[] args) { Scanner sc=new Scanner(System.in); int min=Integer.MAX_VALUE; System.out.println(...

import java.util.Scanner; public class InputNum { public static void main(String[] args) { System.out.println("请输入10个数,以回车间隔:"); Scanner sr = new Scanner(System.in); int []numArr = new int[10]; for(int i = 0;i

public class Main { public static void main(String[] args) { System.out.println("请输入任意10个整数"); Scanner s=new Scanner(System.in); int num[]=new int[10]; int temp; for(int i=0;i

import java.util.Scanner; public class InputTest { public static void main(String[] args) { Scanner in = new Scanner(System.in); // Scanner类 int[] inputnum = new int[10]; for (int i = 0; i < 10; i++) { // for循环接收int型数据 ...

import java.util.Scanner; public class test1 { public static void main(String[] args) { Scanner sc = new Scanner(System.in); int a[] = new int [10]; for(int i=0;i=0;j-- ){ System.out.print(a[j]+" "); } } } 这个应该是你要的吧

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